A special dice with numbers 1,-1,2,-2,0 and 3 is thrown thrice. What is the probability that the sum of the numbers occurring on the upper face is zero?

Explanation

Below are the cases, when sum of numbers of all dice can be `0`.

`(i) (0,0,0) - 1` possibility

`(ii)(1,0,-1) - 3! = 6` posiibilities

`(iii)(2,0,-2) - 3! = 6` posiibilities

`(iv)(1,1,-2) - (3!)/2= 3` possibilities

`(v)(-1,-2,3) - 3! = 6` posiibilities

`(vi)(2, -1,-1) -(3!)/2= 3` possibilities

So, total number of favourable outcomes, `n(E) = 1+6+6+3+6+3 = 25`

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