In triangle ABC, `R (b + c) = a sqrt(bc)`, where R is the circumradius of the triangle. Then the triangle is

In a triangle ABC, R(b+c)= a sqrt(bc) where R is the circum radius of the triangle. Then the triaangle is

In triangle ABC,R(b+c)=a sqrt(bc), whereR is the circumradius of the triangle.Then the triangle is a)isosceles but not right bright but not isosceles c)right isosceles dequilateral

In triangle A B C ,R(b+c)=asqrt(b c),w h e r eR is the circumradius of the triangle. Then the triangle is a)isosceles but not right b)right but not isosceles c)right isosceles d)equilateral

In triangle A B C ,R(b+c)=asqrt(b c),w h e r eR is the circumradius of the triangle. Then the triangle is a)isosceles but not right b)right but not isosceles c)right isosceles d)equilateral

In triangle A B C ,R(b+c)=asqrt(b c),w h e r eR is the circumradius of the triangle. Then the triangle is a)isosceles but not right b)right but not isosceles c)right isosceles d)equilateral

If R_(1) is the circumradius of the pedal triangle of a given triangle ABC, and R_(2) is the circumradius of the pedal triangle of the pedal triangle formed, and so on R_(3), R_(4) …… then the value of sum_(i=1)^(infty) R_(i) , where R (circumradius) of Delta ABC is 5 is

In a triangle ABC let angle C=pi//2 . If r is the inradius and R is the circumradius of the the triangle ABC, then 2(r+R)=

In triangle ABC, let angle C = pi//2 . If r is the inradius and R is circumradius of the triangle, then 2(r + R) is equal to

In triangle ABC, let angle C = pi//2 . If r is the inradius and R is circumradius of the triangle, then 2(r + R) is equal to