The de Broglie wavelength of an electron accelerated by an electric field of V volt is given by:

The de Broglie wavelength lamda of an electron accelerated through a potential V in volts is

The de Broglie wavelength lamda of an electron accelerated through a potential V in volts is

The de Broglie wavelength associated with an electron accelerated by a potential of 64 V is

Show that the de Broglie wavelength of charged particles accelerated through a potential of V volt is given by lamda = h//sqrt(2mqV) . Hence show that the de-Broglie wavelength of electron is (12.27)/(sqrtV)Å .

Determine de Broglie wavelength of an electron accelerated through a potential difference of V volt.

de Broglie wavelength of an electron after being accelerated by a potential difference of V volt from rest is :

de Broglie wavelength of an electron after being accelerated by a potential difference of V volt from rest is :

de Broglie wavelength of an electron after being accelerated by a potential difference of V volt from rest is :