`A` spherical ball of radius `7cm` contains `56%` iron. If density is `1.4 g//cm^(3)`, number of mol of `Fe` present approximately is :

A spherical ball of radius 7cm contains 56% iron. If density is 1.4g"/"cm^(3) , number of moles of Fe present approximately is

A spherical ball of radius 3 cm contains 66.66% iron. If density of ball is 1.5 g/ cm^3 then the number of mole of Fe present approximately is:

A spherical ball of radius 3 cm contains 66.66% iron. If density of ball is 1.5 g/ cm^3 then the number of mole of Fe present approximately is:

A spherical ball of radius 7 cm contains 56 w % iron. Find out the number of moles of iron present approximately in the ball ? ( d=1.4 g cm^(-3) , atomic mass = 56 g "mol"^(-1) )

A sphere of radius 7 cm contains 56% iron. If the density of the sphere is 1.4g/ cm^(3) , then the approximate amount of iron present is-

A spherical ball of lead of radius 14 cm is melted and recast into spheres of radius 2 cm. The number of the small spheres is

A solid spherical ball of iron of radius 4 cm is melted to form spheres of radius 2 cm each The number of spheres so formed is