In`DeltaP Q R~=DeltaE F D ,` Which side of`DeltaP Q R` equals `E D ?` Which angle of`DeltaP Q R` equals `/_E ?`

Two sides AB and BC and median AM of one triangle ABC are respectively equal to side PQ and QR and median PN of DeltaA B C~=DeltaP Q R (see Fig. 7.40). Show that: (i) DeltaA B M~=DeltaP Q N (ii) DeltaA B C~=DeltaP Q R

In figure Cm and RN are respectively the medians of DeltaA B C and DeltaP Q R . If DeltaA B C ~DeltaP Q R , prove that: (i) DeltaA M C ~DeltaP N R (ii) (C M)/(R N)=(A B)/(P Q) (ii) DeltaC M B ~DeltaR N Q

P alpha Q means P is greater than Q. P beta Q means P is either greater than or equal to Q. P gamma Q means P is equal to Q. P delta Q means P is smaller than Q. P eta Q means P is either smaller than or equal to Q. Statements: E gamma F, C delta D, F beta G, D alpha E conclusions: I. E alpha G II. C gamma E

Let Delta denote the area of the DeltaABCand Delta p be the area of its pedal triangle. If Delta=k Deltap, then k is equal to

In the following question , the symbols @ , c , $, % and * are used with the following meanings as illustrated below : 'P © Q' means P is not smaller than Q 'P ** Q' means P is not greater than Q. 'P @ Q' means P is neither greater than nor equal to Q. 'P$ Q' means P is neither smaller than nor equal to Q 'P % Q' means P is neither greater than nor smaller than Q. Statement : F % W , W © R , R © M , M$D. Conclusion: I. D@R II.M$F III.R@D IV. R**F

If in DeltaDEF and DeltaPQR , /_D~=/_Q , /_E~=/_R , then which of the following statements is false?

P @ Q means P is greater than Q. P underline"@" Q means P is either greater than or equal to Q. P = Q means P is equal to Q. P © Q means P is smaller than Q. P underline"©" Q means P is either smaller than or equal to Q. G underline"@" F, D underline"©" E, E = F Conclusions: I. E © G II. E = G

P o+ Q means P is greater than Q. P underline"©" Q means P is either greater than or equal to Q. P = Q means P is equal to Q. P @ Q means P is smaller than Q. P underlinecancel("@") Q means P is either smaller than or equal to Q. I. underlinecancel("@") R, D @ I, E = C, R o+ E Conclusions: I. R o+ C II. I = R