Which of the following functions is neither odd nor even?

Options

A. {(1,2),(4,7),(-1,2),(0,4),(-4,7)}
B. {(1,2),(4,7),(-1,-2),(0,0),(-4,-7)}
C. `y=x^(3)-1`
D. `y=x^(2)-1`

Explanation

To determine which of the given functions is neither odd nor even, we need to analyze each option based on the definitions of odd and even functions.

### Definitions:
1. **Even Function**: A function \( f(x) \) is called even if for every \( x \) in the domain, \( f(-x) = f(x) \).
2. **Odd Function**: A function \( f(x) \) is called odd if for every \( x \) in the domain, \( f(-x) = -f(x) \).

### Step-by-Step Solution:

1. **Check Option A**:
- Let's denote the function as \( f(x) \).
- For \( x = 1 \), suppose \( f(1) = 2 \).
- For \( x = -1 \), suppose \( f(-1) = 2 \).
- Since \( f(-1) = f(1) \), this means \( f(x) \) is even.

**Conclusion for Option A**: This function is even.

2. **Check Option B**:
- Let's denote the function as \( g(x) \).
- For \( x = 1 \), suppose \( g(1) = 2 \).
- For \( x = -1 \), suppose \( g(-1) = -2 \).
- Here, \( g(-1) = -g(1) \), which means \( g(x) \) is odd.

**Conclusion for Option B**: This function is odd.

3. **Check Option C**:
- Let's denote the function as \( h(x) \).
- For \( x = 1 \), \( h(1) = 1^3 - 1 = 0 \).
- For \( x = -1 \), \( h(-1) = (-1)^3 - 1 = -1 - 1 = -2 \).
- Now, we check:
- For even: \( h(-1) \neq h(1) \) (since \(-2 \neq 0\)).
- For odd: \( h(-1) \neq -h(1) \) (since \(-2 \neq -0\)).
- Therefore, this function does not satisfy the conditions for being either even or odd.

**Conclusion for Option C**: This function is neither odd nor even.

### Final Answer:
The function that is neither odd nor even is **Option C**.