Solve `2x^(2)-8x+6=0` by completing the square.

Explanation

First divide both sides of the equation by 2, to make the coefficient of `x^(2)` equal to 1: `x^(2)-4x+3=0`. Next, isolate the constant term by subtracting 3 from both sides of the equation: `x^(2)-4x=-3`, and add the square of half the linear coefficient (-4) to both sides: `x^(2)-4x+4=1`, the left side of the equation is now a perfect square: `(x-2)^(2)=1`. taking the positive and negative square roots, we get `x-2=1` or `x-2=-1`. therefore, x=3 or x=1.