The sum of the zeros of `y=3x^(2)-6x-4` is

Options

A. `-2`
B. `-(4)/(3)`
C. `(4)/(3)`
D. `2`

Explanation

To find the sum of the zeros of the quadratic function \( y = 3x^2 - 6x - 4 \), we can use the formula for the sum of the zeros of a quadratic equation of the form \( y = ax^2 + bx + c \).

### Step-by-Step Solution:

1. **Identify the coefficients**:
From the given quadratic equation \( y = 3x^2 - 6x - 4 \), we identify:
- \( a = 3 \) (the coefficient of \( x^2 \))
- \( b = -6 \) (the coefficient of \( x \))
- \( c = -4 \) (the constant term)

2. **Use the formula for the sum of the zeros**:
The sum of the zeros of a quadratic equation is given by the formula:
\[ \text{Sum of zeros} = -\frac{b}{a} \]

3. **Substitute the values of \( a \) and \( b \)**:
Substitute \( b = -6 \) and \( a = 3 \) into the formula:
\[ \text{Sum of zeros} = -\frac{-6}{3} \]

4. **Simplify the expression**:
Simplifying the expression gives:
\[ \text{Sum of zeros} = \frac{6}{3} = 2 \]

5. **Final answer**:
Therefore, the sum of the zeros of the quadratic function \( y = 3x^2 - 6x - 4 \) is \( 2 \).