Graph the parametric euation `{:{(x=3t+4),(y=t-5):}`
Text Solution
AI Generated Solution
To graph the parametric equations given by \( x = 3t + 4 \) and \( y = t - 5 \), we will follow these steps:
### Step 1: Eliminate the parameter \( t \)
We start by expressing \( t \) in terms of \( y \) from the equation for \( y \):
\[
y = t - 5 \implies t = y + 5
\]
...
Topper's Solved these Questions
PARAMETRIC EQUATIONS
ENGLISH SAT|Exercise EXERCISES|3 Videos
MODEL TEST 6
ENGLISH SAT|Exercise MCQS|50 Videos
PASSPORT TO ADVANCED MATH
ENGLISH SAT|Exercise EXERCISE|80 Videos
Similar Questions
Explore conceptually related problems
Sketch the graph of the parametric equation {:{(x=4 cos theta),(y=3 sin theta):}
Find the cartesian equation of the curve whose parametric equations are : x=t, y=3t+5
Find the cartesian equation of the curve whose parametric equations are : x=t, y=t^(2)
Show that the function y=f(x) defined by the parametric equations x=e^(t)sin(t),y=e^(t).cos(t), satisfies the relation y''(x+y)^(2)=2(xy'-y)
The length of latusrectum of the parabola whose parametric equations are x=t^2+t+1,y=t^2-t+1, where t in R is equal to (1) sqrt(2) (2) sqrt(4) (3) sqrt(8) (4) sqrt(6)
If 0 le t le 1 , which of the following graphs is the graph of y versus x where x and y are related by the parametric equations y=t^(2) and x = sqrt(t) ?
The graph of y=(x+2)(2x-3) can be expressed as a set of parametric equations. If x=2t-2 and y=f(t) , then f(t)=
Find the Cartesian equation of the curves whose parametric equation are : x = (20t)/(4+t^2) , y = (5(4-t^2))/(4+t^2)
If a curve is represented parametrically by the equation x=f(t) and y=g(t)" then prove that "(d^(2)y)/(dx^(2))=-[(g'(t))/(f'(t))]^(3)((d^(2)x)/(dy^(2)))