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The first three terms of a geometric seq...

The first three terms of a geometric sequence are `root4(3), root8(3),1.` The fourth term is

A

`root(32)(3)`

B

`root(16)(3)`

C

`(1)/(root(16)(3))`

D

`(1)/(root8(3))`

Text Solution

Verified by Experts

The correct Answer is:
D
Terms are `3^(1//4), 3^(1//8),1`. Common ratio `=3^(-1//8)`. Therefore, the fourth term is
`1.3^(-1//8)=3^(-1//8) or (1)/(root8(3)).`
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