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Suppose costheta=u in 0 lt theta lt (pi)...

Suppose `costheta=u` in `0 lt theta lt (pi)/(2)`. Then `tantheta=`

A

1

B

`(1)/(sqrt(1-u^(2)))`

C

`(u)/(sqrt(1-u^(2)))`

D

`(sqrt(1-u^(2)))/(u)`

Text Solution

Verified by Experts

The correct Answer is:
D
Since `0 lt theta lt (pi)/(2)`, the figure below shows `theta` in Quadrant 1 with `costheta=u`.

From the figure `tantheta=(sqrt(1-u^(2)))/(u)`.
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