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A pair of dice is tossed 10 times. What ...

A pair of dice is tossed 10 times. What is the probability that no 7s or 11s appear as the sum of the sides facing up ?

A

0.08

B

0.09

C

0.11

D

0.16

Text Solution

Verified by Experts

The correct Answer is:
A
There are six ways to get a 7 and two ways to get an 11 on two dice, and so there are 36-8=28 ways to get anything else. Therefore , P(no 7 or 11)=
P(always getting something else)=`((28)/(36))^(10)~~0.08`
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