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If the longer diagonal of a rhombus is 1...

If the longer diagonal of a rhombus is 10 and the large angle is `100^(@)` , what is the area of the rhombus ?

A

37

B

40

C

42

D

45

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The correct Answer is:
To find the area of the rhombus given that the longer diagonal is 10 and the larger angle is \(100^\circ\), we can follow these steps: ### Step 1: Understand the properties of the rhombus A rhombus has diagonals that bisect each other at right angles. This means that if we denote the diagonals as \(AC\) and \(BD\), they intersect at point \(O\) such that \(AO = OC\) and \(BO = OD\). ### Step 2: Identify the diagonals Given that the longer diagonal \(BD = 10\), we can find the lengths of \(BO\) and \(OD\): \[ BO = OD = \frac{BD}{2} = \frac{10}{2} = 5 \] ### Step 3: Analyze the angles Since the diagonals bisect the angles of the rhombus, we can denote the larger angle \(A\) as \(100^\circ\). The angle \(BAO\) will be half of angle \(A\): \[ \angle BAO = \frac{100^\circ}{2} = 50^\circ \] Since the diagonals intersect at right angles, we have: \[ \angle AOB = 90^\circ \] Now, we can find angle \(ABO\) using the fact that the sum of angles in triangle \(ABO\) is \(180^\circ\): \[ \angle ABO = 180^\circ - \angle BAO - \angle AOB = 180^\circ - 50^\circ - 90^\circ = 40^\circ \] ### Step 4: Use trigonometry to find \(AO\) We can use the tangent function to find the length \(AO\): \[ \tan(\angle ABO) = \frac{AO}{BO} \] Substituting the known values: \[ \tan(40^\circ) = \frac{AO}{5} \] Thus, \[ AO = 5 \tan(40^\circ) \] ### Step 5: Calculate \(AO\) Using a calculator or trigonometric table, we find: \[ \tan(40^\circ) \approx 0.8391 \] So, \[ AO \approx 5 \times 0.8391 \approx 4.1955 \] ### Step 6: Find the length of diagonal \(AC\) Since \(AO\) is half of diagonal \(AC\): \[ AC = 2 \times AO \approx 2 \times 4.1955 \approx 8.391 \] ### Step 7: Calculate the area of the rhombus The area \(A\) of a rhombus can be calculated using the formula: \[ A = \frac{1}{2} \times AC \times BD \] Substituting the values we found: \[ A = \frac{1}{2} \times 8.391 \times 10 \approx \frac{83.91}{2} \approx 41.955 \] ### Final Answer Thus, the area of the rhombus is approximately \(42\) square units. ---

To find the area of the rhombus given that the longer diagonal is 10 and the larger angle is \(100^\circ\), we can follow these steps: ### Step 1: Understand the properties of the rhombus A rhombus has diagonals that bisect each other at right angles. This means that if we denote the diagonals as \(AC\) and \(BD\), they intersect at point \(O\) such that \(AO = OC\) and \(BO = OD\). ### Step 2: Identify the diagonals Given that the longer diagonal \(BD = 10\), we can find the lengths of \(BO\) and \(OD\): \[ ...
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