In figure, find the horizontal velocity `u (in ms^(-1))` of a projectile so that it hits the inclined plane perpendicularly. Given `H = 6.25m`.

In the given figure , the angle of inclination of the inclined plane is 30^(@) . A particle is projected with horizontal velocity v_(0) from height H. Find the horizotnal velocity v_(0) (in m/s) so that the particle hits the inclined plane perpendicu lar .Given H=4m, g =10m//s^(2) .

In figure, the angle of inclination of the inclined plane is 30^@ . Find the horizontal velocity V_0 so that the particle hits the inclined plane perpendicularly. .

In figure, the angle of inclination of the inclined plane is 30^@ . Find the horizontal velocity V_0 so that the particle hits the inclined plane perpendicularly. .

Determine the horizontal velocity v_0 with which a stone must be projected horizontally from a point P, so that it may hit the inclined plane perpendicularly. The inclination of the plane with the horizontal is theta and point P is at a height h above the foot of the incline, as shown in the figure.

Determine the horizontal velocity v_0 with which a stone must be projected horizontally from a point P, so that it may hit the inclined plane perpendicularly. The inclination of the plane with the horizontal is theta and point P is at a height h above the foot of the incline, as shown in the figure.

A stone must be projected horizontally from a point P, which is h meter above the foot of a plane inclined at an angle theta with horizontal as shown in figure . Calculate the velocity v of the stone so that in may hit the incline plane perpendiculary.

A particle is projected horizontally with spee u from point A, which is 10 above the ground . If the particle hits the inclined perpendicularly at point B. [ g = 10 m//s^(2)] Find the length OB along the inclined plane