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1^(2)-2sqrt(6)y+2=...

1^(2)-2sqrt(6)y+2=

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If the line 2x+sqrt(6)y=2 touches the hyperbola x^2-2y^2=4 , then the point of contact is (-2,sqrt(6)) (b) (-5,2sqrt(6)) (1/2,1/(sqrt(6))) (d) (4,-sqrt(6))

(sqrt(2) + 1)^(6) - (sqrt(2) -1)^(6) is equal to

(sqrt(2) + 1)^(6) - (sqrt(2) -1)^(6) is equal to

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The value of sqrt(6+2sqrt(3)+2sqrt(2)+2sqrt(6))-(1)/(sqrt(5-2sqrt(6))) is

Show that : (1)/(3-2sqrt(2))- (1)/(2sqrt(2)-sqrt(7)) + (1)/(sqrt(7)-sqrt(6))-(1)/(sqrt(6)-sqrt(5))+(1)/(sqrt(5)-2)=5 .