Simplify : `(25\ xx\ a^(-4))/(5^(-3)\ xx\ 10\ xx\ a^(-8))` (ii) `(3^(-5)\ xx\ 10^(-5)\ xx\ 125)/(5^(-7)\xx\ 6^(-5))`

Explanation

(i)`(25\ xx\ a^(-4))/(5^(-3)\ xx\ 10\ xx\ a^(-8))`
`(25xxa^8xx5^3)/10xx1/a^4`
`(625xxa^4)/2`
`(625 a^4)/2`
(ii) `(3^(-5)\ xx\ 10^(-5)\ xx\ 125)/(5^(-7)\xx\ 6^(-5))`
`(5^7xx6^5xx125)/(3^5xx10^5)`
Cancelling the numbers, we have,
`25xx125`
`3125`.