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Find x , if (3/2)^(-3)xx\ (3/2)^5=(3/2)...

Find `x` , if `(3/2)^(-3)xx\ (3/2)^5=(3/2)^(2x+1)`

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`(3/2)^(-3)xx\ (3/2)^5=(3/2)^(2x+1)`
`=>(3/2)^2=(3/2)^(2x+1)`
On comparing the powers,
`=>2x+1=2`
`=>x=1/2`
Hence, the value of `x` is `1/2`.
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