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Find x , if (8/3)^(2x+1)xx(8/3)^5=(8/3)...

Find `x` , if `(8/3)^(2x+1)xx(8/3)^5=(8/3)^(x+2)`

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`(8/3)^(2x+1)xx(8/3)^5=(8/3)^(x+2)`
`=>(8/3)^(2x+6)=(8/3)^(x+2)`
`=>2x+6=x+2`
`=>x=-4`
Hence, the value of `x` is `-4`.
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