Write a Pythagorean triplet whose one member is : (I)6             (ii)  18

Explanation

(i)As we know, the Pythagorean triplet for any number are `2m`, `m^2+1` and `m^2-1`
Let `2m=6`
`m=3`
`m^2+1=3^2+1=10`.
`m^2-1=3^2-1=8`
Hence, the Pythagorean triplet is `6`, `8` and `10`.

(ii)As we know, the Pythagorean triplet for any number are `2m`, `m^2+1` and `m^2-1`
Let `2m=18`
`m=9`
`m^2+1=9^2+1=82`.
`m^2-1=9^2-1=80`
Hence, the Pythagorean triplet is `18`, `80` and `82`.