Observe the following pattern `2^2-1^2=2+1` `3^2-2^2=3+2` `4^2-3^2=4+3` `5^2-4^2=5+4` and find the value of (I)`100^2-99^2` (ii) `111^2-109^2` (iii) `99^2-96^2`

Explanation

To solve the given problems, we will use the pattern observed in the provided equations. The pattern states that:

\[ a^2 - b^2 = a + b \]

where \( a \) and \( b \) are consecutive integers.

### Step-by-Step Solution:

...