Write the cubes of 5 natural numbers of the form `3n+2(idote .5 ,8, 11 , )` and verify the following : The cube of a natural number of the form `3n+2\ ` is a natural number of the same form i.e. when it is dividend by 3 the remainder is 2

Explanation

To solve the problem, we need to find the cubes of 5 natural numbers of the form \(3n + 2\) and then verify that their cubes also fall into the same form \(3n + 2\).

### Step-by-Step Solution:

**Step 1: Identify 5 natural numbers of the form \(3n + 2\)**
The natural numbers that fit the form \(3n + 2\) can be generated by substituting different values of \(n\).
- For \(n = 0\): \(3(0) + 2 = 2\)
- For \(n = 1\): \(3(1) + 2 = 5\)
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