Write the cubes of 5 natural numbers of which are multiples of 7 and verify the following : The cube of multiple of 7 is a multiple of `7^3dot`

Explanation

First `5` natural numbers which are multiples of `7` are:
`14`, `21`, `28`, `35` and `42`.
Now, cubes of these numbers are following :
`14^3=2744`
`21^3=9261`
`28^3=21952`
`35^3=42875`
`42^3=74088`

Now, to verify that these cubes are multiple of `7^3` we divide all these numbers by `7^3=343`
`2744/343=8`
`9261/343=27`
`21952/343=64`
`42875/343=125`
`74088/343=216`
Hence, we can say that the cube of a multiple of `7` ia a multiple of `7^3`.