Evaluate each of the following : (i) `root3 (27) +root3( 0. 008)+ root3 (0. 064)`
(i) `root3(1000) + root3 (0. 008)-root3(0. 125)`
(iii)`root3((729)/(216)) xx6/9`
(iv) `root3((0. 027)/(0. 008)) -: root3((0. 09)/(0. 04))-1`
(v) `root3 (0. 1 xx 0. 1 xx 0. 1 xx 13xx 13 xx 13) `

Explanation

`(i)root3(27)+ root3(0. 008)+root3(0. 064)`

`=>root3(3xx3xx3) + root3(8/1000) + root3(64/1000)`

`=>3 + root3(2xx2xx2//10xx10xx10) + root3(4xx4xx4//10xx10xx10)`

`=>3 + 2/10+ 4/10`

`=>3 + 0.2+ 0.4`

`=>3.6`

`(ii)root3(1000)+root3(0. 008)-root3(0.125)`

`=>root3(10xx10xx10) + root3(8/1000) - root3(125/1000)`

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