Fill in the blanks: `125\ x\ 27 3=3\ x dot` (ii) `8\ x =8 3` `1728 3=4\ x ` (iv) `480 3=\ 3 3\ x\ 2\ x\ 3` `\ 3=7 3\ x\ 8 3` (vi) `3=\ 4 3\ x\ 5 3\ x\ 6 3` `(27)/(125)3=\ /5` (viii) `(729)/(1331)3=9/` `(512)/3=8/(13)`

Explanation

`(i)root3((125xx 27))=3xxldots`

`=>root3((5xx5xx5xx3xx3xx3))`
`=>root3((5^3 xx 3^3))`

`=>5xx3 or 3xx5`

`(ii)root3((8xx ldots))=8`

`=>root3((8xx8xx8))=root3(8^3)`

`=>8`

`(iii)root(3)1728=4 xx ldots`

`=>"by Prime Factorising",`

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