If `x` is a digit such that the number ` 18 x 71 ` is divisible by 3. find possible values of `x` .

Explanation

As we know that numbers are divisible by `3` if the sum of all the individual digits is evenly divisible by `3`.
Given number `=18×71`
The sum of all the digits of `18×71`
`= 1 + 8 + 7 + 1 = 17`
`17` is not divisible by `3`, so we need `18`, which is divisible by `3`.
`17 + 1 = 18`
So, the values of `x` are `1, 4` and `7`.
And, the numbers are `18171,18471` and `18771.`