Solve the cryptarithm: `B A x\ \ B3 5\ \ 7A`

Explanation

Given:`BAtimesB3=57A`
If we multiply any number `x` with `3` and we get a number `x` in unit digit, then `x` is either `5` or `0`.
So, in the given question, `A` can be `5` or `0`.
If, `A` is `5`, then, the result is `575`.
Then, `3timesB+1` can be `7`.
So, `B` can be `2`.
If we try `A=3` and `B=2`, it satisfies this multiplication.
So, `575` is the right answer.