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Multiply -3/2x^2y^2\ by\ (2x-y) and ver...

Multiply `-3/2x^2y^2\ ` by`\ (2x-y)` and verify the answer for `x=1\ ` and`\ y=2.`

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`− 3/2 x^2 y^2 xx ( 2 x − y ) −3/2x^2y^2 xx(2x−y) `
`= -3x^4y^3 + 3/2x^3y^3.`
According to question: When` x = 1` and `y = 2`
`= -3 (1)^4 (2)^3+3/2(1)^3 (2)^4`
`= -3 (8) + 3 (8)`
`= 0`
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