[" Consider the equation "x^(2)+2x-n=0" ,where "n in N" and "n in[5,100]" .Total num "],[" different values of 'n' so that the given equation has integral roots,is "]

Consider the equation x^(2) + 2x - n = 0 m where n in N and n in [5, 100] . The total number of different values of n so that the given equation has integral roots is

Consider the equation x^(2)+2x-n=0 where n in N and n in[5,100] The total number of different values of n so that the given equation has integral roots is a.8 b.3 c. 6d.4

Consider the equation x^2+2x-n=0 where n in N and n in [5,100] The total number of different values of n so that the given equation has integral roots is a. 8 b. 3 c. 6 d. 4

Consider the equation x^2+2x-n=0 where n in N and n in [5,100] The total number of different values of n so that the given equation has integral roots is a. 8 b. 3 c. 6 d. 4

Consider the equation x^2+2x-n=0 where n in N and n in [5,100] The total number of different values of n so that the given equation has integral roots is a. 8 b. 3 c. 6 d. 4

consider the equation x^(2)+x-n=0 where a is an integer lying between 1 to 100. Total number of different values of n so that the equation has integral roots,is

The number of integral values of n such that the equation 2n{x}=3x+2[x]has exactly 5 solutions.

Consider the cubic equation f(x)=x^(3)-nx+1=0 where n ge3, n in N then f(x)=0 has

Consider the cubic equation f(x)=x^(3)-nx+1=0 where n ge3, n in N then f(x)=0 has