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cos4x=1-8sin^(2)x...

cos4x=1-8sin^(2)x

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Prove that : cos4x=1-8sin^2xcos^2x

Prove that cos 4(x)=1-8 sin ^(2) (x) cos ^(2) (x)

cos 4x =1- 8 sin ^(2) x cos ^(2) x

cos 4x =1- 8 sin ^(2) x cos ^(2) x

cos 4x =1- 8 sin ^(2) x cos ^(2) x

cos 4x =1- 8 sin ^(2) x cos ^(2) x

cos 4x =1- 8 sin ^(2) x cos ^(2) x

Prove the following: cos 4x = 1 - 8sin^2 x cos^2 x

The minimum value of 1-8sin^(2) x cos^(2) x is