x=a cos(theta)/(2),y=b sin(theta)/(2)

Find locus of points given by x=a cos^(2)theta,y=b sin^(2)theta

If x=a cos^(2)theta,y=b sin^(2)theta find (d^2y)/dx^2

If x(cos theta)/(a)+y(sin theta)/(b)=1 and x(sin theta)/(a)-y(sin theta)/(b)=1 then

Eliminate theta between x sin theta-ycos theta =sqrt(x^2+y^2) and (cos^2theta)/(a^2)+(sin^2theta)/(b^2)=1/(x^2+y^2) .

If x = a cos^(2) theta, y = b sin^(2) theta " then "(dy)/(dx)= ?

Find dy/dx , if x and y are connected parametrically by the equations, given below without eliminating the parameter. x = a cos^2 theta, y = b sin^2 theta

Eliminate theta : x = a ( cos theta + cos 2 theta), y = b ( sin theta + sin 2 theta).

Find (dy)/(dx) if x =a cos ^(2) theta , y =b sin ^(2) theta .

If (x)/(a) cos theta + (y)/(b) sin theta = 1 , (x)/(a) sin theta - (y)/(b) cos theta =1 then

If x = (sin^(3)theta)/(cos^(2) theta)and y = (cos^(3) theta)/(sin^(2)theta) , where sin theta + cos theta = (1)/(2) , " then " x + y =