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In a box, there are 8 red, 7 blue and 6 ...

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green ?

Text Solution

Verified by Experts

Number of red balls ` = 8`
Number of blue balls ` = 7`
Number of green balls ` = 6`
Total number of balls ` = 8+7+6 = 21`
If the ball drawn is neither red nor green, it means the ball drawn is blue.
So, probability of drawing a blue ball ` = 7/21 = 1/3`
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