Divide: `3y^5+6y^4+6y^3+7y^2+8y+9\ b y\ 3y^3+1` and verify that dividend=divisor`xx` quotient+ remainder

Explanation

To solve the problem of dividing the polynomial \(3y^5 + 6y^4 + 6y^3 + 7y^2 + 8y + 9\) by \(3y^3 + 1\), we will use the long division method for polynomials. Let's go through the steps one by one.

### Step-by-Step Solution

1. **Set Up the Division**:
We will write the dividend \(3y^5 + 6y^4 + 6y^3 + 7y^2 + 8y + 9\) under the long division symbol and the divisor \(3y^3 + 1\) outside.

**Hint**: Always write the dividend and divisor clearly to avoid confusion during the division process.
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