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Solve: (x+2)/3-(x+1)/5=(x-3)/4-1...

Solve: `(x+2)/3-(x+1)/5=(x-3)/4-1`

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`(x+2)/3-(x+1)/5=(x-3)/4-1`
`=>5x + 10 - 3x - 3/15 = (x - 7)/4`
`=>(2x + 7)/15 = (x - 7)/4`
`=>4(2x + 7) = 15(x - 7)`
`=>8x + 28 = 15x - 105 `
`=>8x - 15x = - 105 - 28`
`=>- 7x = - 133`
`=>x = - 133/- 7`
`=>x = 19`
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