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Solve: (2x+3)^2+(2x-3)^2=(8x+6)(x-1)+...

Solve: `(2x+3)^2+(2x-3)^2=(8x+6)(x-1)+22`

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To solve the equation \((2x+3)^2+(2x-3)^2=(8x+6)(x-1)+22\), we will follow these steps: ### Step 1: Expand the left side of the equation Using the identities for the square of a binomial: - \((a + b)^2 = a^2 + 2ab + b^2\) - \((a - b)^2 = a^2 - 2ab + b^2\) We can expand \((2x + 3)^2\) and \((2x - 3)^2\): ...
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