Divide 184 into two parts such that one-third of one part may exceed one-seventh of the other part by 8.

Explanation

Let one part be `x`
Other part`=(184-x)`
According to the question:
`(1/3timesx)-[1/7times(184-x)]=8`
`x/3 - (184/7-x/7)=8`
`x/3-184/7+x/7=8`
`x/3+x/7-184/7=8`
`x/3+x/7=8+184/7`
`(7x+3x)/21=(56+184)/7`
`10x/21=240/7`
`x = 240/7times21/10`
`x=72`
`therefore` One part`=72`
Other part`=184-72=112`