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The numerator of a fraction is 6 less then the denominator. If 3 is added to the numerator, the fraction is equal to `2/3` . What is the original fraction equal to ?

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Given:
The numerator of a fraction is `6` less then the denominator.
If `3` is added to the numerator, the fraction is equal to `2/3`
Let the denominator be `x`.
Then, the numerator will be `x-6`.
According to the question,
When `3` is added in the numerator,
`(x-6+3)/x=2/3`
`(x-3)/x=2/3`
`3(x-3)=2x`
`3x-9=2x`
`3x-2x=9`
`x=9`
The numerator is `x-6=9-6=3`
The denominator is `x=9`.
Hence, the original fraction is `3/9`.
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