Sunita is twice as old as Ashima. If six years is subtracted from Ashima’s and four years added to Sunita’s age, then Sunita wil be four times Ashima’s age. How old were they two years age?

Explanation

Let the present age of Ashima be `x` years.
The present age of Sunita is `2x` years.
Ashima’s new age `=(x-6)` years.
Sunita’s new age `=(2x+4)` years.
According to question,
`(2x+4)=4(x-6)`
`2x+4=4x–24`
`2x-4x=-24-4`
`-2x=-28`
`x=-(28)/-2=14`
The age of Ashima is `x=14` years.
The age of Sunita is `2x` years`=2times14=28` years.
Two years ago, age of Ashima is `14-2=12` years and age of Sunita `=28-2=26` years.
Hence, the age of Sunita and Ashima two years ago was `12` years and `26` years.