The `pH` of a solution containing `0.1mol` of `CH_(3)COOH, 0.2 mol` of `CH_(3)COONa`,and `0.05 mol` of `NaOH` in `1L. (pK_(a) of CH_(3)COOH = 4.74)` is:

To 1.0L solution containing 0.1mol each of NH_(3) and NH_(4)C1,0.05mol NaOH is added. The change in pH will be (pK_(a) for CH_(3)COOH = 4.74)

To 1.0L solution containing 0.1mol each of NH_(3) and NH_(4)C1,0.05mol NaOH is added. The change in pH will be (pK_(a) for CH_(3)COOH = 4.74)

The pH of a solution resulting from the addition of 12.5mL of 0.1M HCl to 50mL of a solution containing 0.15M CH_(3)COOH & 0.2M CH_(3)COONa will be (Given : pK_(a) of CH_(3)COOH=4.74 )

Calculate pH of a solution of given mixture ( 0.1 "mol " CH_(3)COOH+0.2 mol CH_(3)COONa ) in 100 ml of mixture. K=2xx10^(-5) .

The ratio of the pH of solution (I) containing 1 mol of CH_(3)COONa and 1 mol of HCl in 1L, and solution (II) containing 1 mol of CH_(3)COONa and 1 mol of CH_(3)COOH in 1L is