A dealer bought two tables for Rs 3120. He sold one of them at a loss of 15% and other at a gain of 36%. Them he found that each table was sold for the same price. Find the cost price of each table.,

Explanation

Given in question, Total price of two boxes = `3120`

Let CP of one box = x
CP of another box = `(3120 - x)`
Profit on 1st box = `20%`
SP of 1st box =` y +( 20y)/(100)`
SP of 1st box`= 100y +( 20y)/(100)`= `(120y)/100`
Loss on 2nd box = `12%`
SP of 2nd box = CP - Loss
SP of 2nd box =` (1300-y) (1-12/100)`
SP of 2nd box = `1144-(88y)/(100)`

But SP of both boxes is same `(120y)/(100)+(88y)/(100)=1144`

`(208y)/100 = 1144`
`y=1144*100/208 = 550`