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170xx14div181=?...

`170xx14div181=?`

A

3

B

13

C

33

D

53

Text Solution

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The correct Answer is:
To solve the problem \( 170 \times \frac{14}{181} \), we will use approximation to simplify our calculations. Here’s a step-by-step breakdown: ### Step 1: Understand the Problem We need to calculate \( 170 \times \frac{14}{181} \). The division \( \frac{14}{181} \) is not straightforward, so we will approximate \( 181 \) to make the calculation easier. **Hint:** Look for a nearby number that is easier to work with for division. ### Step 2: Approximate the Denominator We can approximate \( 181 \) to \( 182 \) because it is close and makes calculations easier. **Hint:** Choose a number that is slightly larger than the original for easier division. ### Step 3: Calculate the Approximate Division Now we calculate \( \frac{14}{182} \). We can simplify this: \[ \frac{14}{182} = \frac{14 \div 14}{182 \div 14} = \frac{1}{13} \] **Hint:** Simplifying fractions can make calculations much easier. ### Step 4: Substitute Back into the Equation Now we substitute back into our original equation: \[ 170 \times \frac{1}{13} \] **Hint:** When multiplying by a fraction, think of it as dividing by the denominator. ### Step 5: Calculate the Final Result Now we can calculate: \[ 170 \div 13 \approx 13 \] This is because \( 13 \times 13 = 169 \), which is very close to \( 170 \). **Hint:** Use multiplication tables or quick mental math to estimate divisions. ### Conclusion Thus, the approximate value of \( 170 \times \frac{14}{181} \) is about \( 13 \). **Final Answer:** \( \approx 13 \)

To solve the problem \( 170 \times \frac{14}{181} \), we will use approximation to simplify our calculations. Here’s a step-by-step breakdown: ### Step 1: Understand the Problem We need to calculate \( 170 \times \frac{14}{181} \). The division \( \frac{14}{181} \) is not straightforward, so we will approximate \( 181 \) to make the calculation easier. **Hint:** Look for a nearby number that is easier to work with for division. ### Step 2: Approximate the Denominator ...
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