(?)^(2)+231.001=39.95% "of" 1000.206...

`(?)^(2)+231.001=39.95% "of" 1000.206`

A

13

B

8

C

15

D

14

Text Solution

Verified by Experts

The correct Answer is:

A

`(?)^(2)+231=(40xx1000)/(100)`
`(?)^(2)+231=400`
`rArr (?)^(2)=169`
`rArr ?=13`

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