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Sonika invested an amount of ₹5800 for 2...

Sonika invested an amount of ₹5800 for 2 years. At what rate of compound interest will she get an amount of ₹594.50 at the end of two years?

A

5 pcpa

B

4 pcpa

C

6 pcpa

D

8 pcpa

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The correct Answer is:
To find the rate of compound interest at which Sonika will receive an amount of ₹594.50 after investing ₹5800 for 2 years, we can follow these steps: ### Step 1: Identify the principal amount and the total amount after 2 years - Principal (P) = ₹5800 - Interest earned (I) = ₹594.50 - Total Amount (A) = Principal + Interest = ₹5800 + ₹594.50 = ₹6394.50 ### Step 2: Use the formula for compound interest The formula for the amount in compound interest is: \[ A = P \left(1 + \frac{r}{100}\right)^n \] Where: - \( A \) = Total amount after time \( n \) - \( P \) = Principal amount - \( r \) = Rate of interest per annum - \( n \) = Time in years ### Step 3: Substitute the known values into the formula Substituting the values we have: \[ 6394.50 = 5800 \left(1 + \frac{r}{100}\right)^2 \] ### Step 4: Divide both sides by the principal amount \[ \frac{6394.50}{5800} = \left(1 + \frac{r}{100}\right)^2 \] Calculating the left side: \[ \frac{6394.50}{5800} = 1.1025 \] ### Step 5: Take the square root of both sides To eliminate the square, we take the square root: \[ \sqrt{1.1025} = 1 + \frac{r}{100} \] Calculating the square root: \[ 1.05 = 1 + \frac{r}{100} \] ### Step 6: Solve for the rate of interest Now, we can isolate \( r \): \[ \frac{r}{100} = 1.05 - 1 \] \[ \frac{r}{100} = 0.05 \] Multiplying both sides by 100: \[ r = 5 \] ### Conclusion The rate of compound interest is **5% per annum**. ---

To find the rate of compound interest at which Sonika will receive an amount of ₹594.50 after investing ₹5800 for 2 years, we can follow these steps: ### Step 1: Identify the principal amount and the total amount after 2 years - Principal (P) = ₹5800 - Interest earned (I) = ₹594.50 - Total Amount (A) = Principal + Interest = ₹5800 + ₹594.50 = ₹6394.50 ### Step 2: Use the formula for compound interest ...
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