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Given below in the information about sol...

Given below in the information about solar plants installed in four
differnet colonies W,X, Y, Z . Number of solar plants in colonies W,
X, Y, Z are 24, 20, 15 and 12 respectively. Number of electricity
units produced in one week by one solar plant when they operate
with maximum efficiency in colonies W, X,Y,Z are 2 lakh units /
week , 80000 units/week , 1 Lakh units/week and 1.5 Lakh units/
week respectively. Number of houses in each colony W,X,Y,Z
are 540 , 240 , 150 and 350 respectively . total units produced are
consumed equally by each house in the colony. `to` Different number of solar plants are operated in four different weeks
In first week number of solar plants are operative in colonies W, X,Y, Z are 75`%`, 50`%`,40`%` and 75`%` respectively . In second week
it is 50`%` , 76`%`, 60`%` and 50`%` respectively. In third week it is 75`%`,
100`%` , 80`%` and 50`%` respectively. In fourth week it is 100`%`, 50`%`,
60`%` and 75`%` respectively.
` to` Given below is the three ranges of efficiency of a solar plants
(numer of unit produced /week by one plant)
`{:("Efficiency Type","Range"),("Efficiency1",60%-70%),("Efficiency2",45%-55%),("Efficiency3",30%-40%):}`
`to` level 1 : Consider upper limit of range of efficiency
`to` level 2 : Consider mid of range of efficiency
`to` level 3 : Consider the lower range of efficiency
Eg If a solar plants is operative at efficiency 2 than its level 2
efficiency will ve `= (45+55)/(2) =50`%
Its level 1 efficiency will be 55`%`
lts level 3 efficiency will ve 45`%`
What is the ratio of units consumed par house in colony X
in week 4 operating at level 3 of Efficiency range 3 to the level 3
efficiency range 2 of the colony z ?

A

`20:27`

B

`13 : 19`

C

`15 : 19`

D

`10:33`

Text Solution

Verified by Experts


No. of plants operating in X in fourth week
`=20xx(50)/(100)=10`
Total units consumed at level 3 of efficiency range 3 per house `=(10xx80000xx30)/(240xx100)=1000` units/house
No. of plants operating in Y in second week
`=15xx(60)/(100)=9`
Total units consumed at level 1 of efficiency range 2 `=(9xx1,00000)/(150)xx(55)/(100)=3300` unit/house
Required ratio =10:33
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