A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?

Options

A. a. 50
B. b. 65
C. c. 62
D. d. 58

Explanation

To solve the problem, we will follow these steps:

### Step 1: Define the initial quantities of liquids A and B
Let the total volume of the tin be \( V \) liters. Given that the ratio of liquids A and B is 4:1, we can express the quantities of A and B as:
- Quantity of A = \( \frac{4}{5}V \)
- Quantity of B = \( \frac{1}{5}V \)

### Step 2: Calculate the quantities after removing 45 liters of the mixture
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