The r.m.s. velocity of a gas at a certain temperature is `sqrt(2)` times than that of the oxygen molecules at that temperature. The gas can be

Options

A. `H_(2)`
B. `He`
C. `CH_(4)`
D. `SO_(2)`

Explanation

`v_(ms) prop(1)/(sqrt(M)) rArr (v_(1))/(v_(2)) = sqrt((M_(2))/(M_(1)))`
`therefore (1)/sqrt(2) = sqrt((M_(2))/(32))rArr M_(2) = 16`. Hence the gas is `CH_(4)`