If pressure of `CO_(2)` (real gas ) in a container is given by `P = (RT)/(2V - b) - (a)/(4b^(2))`, then mass of the gas in container is

Options

A. 11 gm
B. 22 gm
C. 33 gm
D. 44 gm

Explanation

(b) Vander wall's gas equation for `mu` mole of real gas
`(P+(mu^(2)a)/(V^(2)))(V-mub)=muRTimpliesP=(muRT)/(V-mub)-(mu^(2)a)/(V^(2))`
on comparing the given equation with this standard equation we get `mu=(1)/(2)`. Hence `mu=(m)/(M)implies` mass of gas
`m=mum=(1)/(2)xx44=22gm`