A pressure cooker contains air at 1 atm and `30^(@)` C . If the safety value of the cooler blows when the inside pressure `ge3` atm , then the maximum temperature of the air, inside the cooker can be

Options

A. `90^(@)`
B. `636^(@)C`
C. `909^(@)C`
D. `363^(@)C`

Answer

B

Explanation

(b) Since volume is constant
Hence `(P_(1))/(P_(2))=(T_(1))/(T_(2))implies(1)/(3)=((273+30))/(T_(2))`
`implies T_(2)=909K=636^(@)C`