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In a parallelogram the sum of any two ad...

In a parallelogram the sum of any two adjacent angles is `180^0dot`

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To prove that in a parallelogram the sum of any two adjacent angles is \(180^\circ\), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Parallelogram**: Let’s consider a parallelogram ABCD, where AD is parallel to BC and AB is parallel to CD. 2. **Understand the Properties of Parallel Lines**: ...
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Knowledge Check

  • In a parallelogram ABCD, the sum of any two consecutive angles is 180^(@) and opposite angles are equal. In a parallelogram ABCD, angleD=115^(@) , determine the measure of angleA and angleB

    A
    `angleA = 85^@ , angleB = 115^@`
    B
    `angleA = 65^@ , angleB = 65^@`
    C
    `angleA = 65^@ , angleB = 115^@`
    D
    `angleA = 75^@ , angleB = 105^@`

  • In a parallelogram ABCD, the sum of any two consecutive angles is 180 degree and opposite angles are equal. In the given figure, find angleA in the parallelogram .

    A
    `90^(@)`
    B
    `60^(@)`
    C
    `30^(@)`
    D
    `110^(@)`

  • In a parallelogram ABCD, the sum of any two consecutive angles is 180^(@) and opposite angles are equal. Find the value of angleQ and angleP , if angleP = 10a and angleR = 50^(@) in a parallelogram PQRS.

    A
    `angle=50^(@), angleP=130^(@)`
    B
    `angleQ=130^(@), angleP=50^(@)`
    C
    `angleQ=100^(@), angleP=120^(@)`
    D
    `angleQ=50^(@)+angleP=100^(@)`

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    In a parallelogram; the bisectors of any two consecutive angles intersect at right angle.

    In a parallelogram,two adjacent angles are supplementary.

    One angle of a parallelogram is 30^(@) more than twice its adjacent angles. Find the measure of its adjacent angle.

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