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In Figure, A B C D is a rhombus with /A ...

In Figure, `A B C D` is a rhombus with `/_A B C=56^0dot` Determine `/_A C Ddot`

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In figure rhombus `ABCD` ,
`angle ABC=56°`
to find `angle ACD dot`
we know that
opposite angle of rhombus are equal to each other
therefore `angle A=angle C` and `angle B=angle D`
also we know that sum of interior angle of a rhombus adds up to `360°`
and also know that the diagonals of a rhombus bisect these angles.
`implies angle A + angle B + angle C+ angle D=360°`.
`implies 2 angle C+2angle B=360°`
since diagonals of a rhombus bisect these angles
therefore,`2(2angleACD)+2(56°)=360°`
`implies 4angle ACD+112°=360°`
`implies angle ACD=(360°-112°)/4`
`angle ACD =62°`
Hence, we get required result.
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