ABCD is a rectangle with length 1 dm and breadth 42 m. The diagonal AC is drawn. Find area of ABCD.

Explanation

As we know, `1`dm=`0.1`m ⇒`10`m`8`dm=`10.8`m
Area of ABCD=Area of(△ADC)+Area(△ABC)
Area of triangle =`1/2`×base×height
⇒Area of ABCD =`1/2×10.8×42+1/2×10.8×42 ` =`10.8×42=453.6m^2`.